Possible Duplicate:
mysql_fetch_array() expects parameter 1 to be resource, boolean given in select
I’m trying to use the second function in this post to check if a URL is an image in PHP. I got it to work on my home computer running WAMP, but when I upload it to my webhost it gives me two errors:
Warning: substr() expects parameter 1 to be string, array given in …/checkifimage.php on line 22
Warning: substr() expects parameter 1 to be string, resource given in …/checkifimage.php on line 22
………………………………………
The wrapper_data entry in the array returned by stream_get_meta_data is defined as mixed and I don’t think you can assume what it will contain. It may contain NULL entries or other arrays… since you explicitly want to find a string maybe:
if(is_array($wrapper_data)){
foreach(array_keys($wrapper_data) as $hh){
if (is_string($wrapper_data[$hh]) &&
substr($wrapper_data[$hh], 0, 19) == “Content-Type: image”) // strlen(“Content-Type: image”) == 19
{
fclose($fp);
return true;
}
}
}Would take care of the problem… but I agree var_dump() to see exactly what you are being passed will help you figure it out.